Question

A block of mass 4 Kg is placed in contact with the front vertically surface of a lorry. The cocificient offriction between the vertically surface and block is 0.8. The lorry is moving with an acceleration of 15ms (g = 10 ms"). The force of friction between lorry and block isIla) 48 Nb) 24 Nc) 40 Nd) Zero​

Answer 1

Answer:

48

Explanation:

Mass of the block = m = 4 kg

Coefficient of friction between the vertically surface and block = 0.8T

Acceleration of the lorry a = 15 m/s

Therefore, the force applied to move the truck is,

F = m×a  

= 4 × 15

= 60

Friction between lorry and block -

= F  × cf

= 60 × 0.8

= 48

Thus, the force of friction between lorry and block is 48.

Answer 2

Explanation:

but answer is c , not 48 ,

plz give me correct explanation