a block of mass 5kg is resting ona rough horizontalsurface for which the coefficient of friction is0.2 . when a force F=40N is applied the acceleration of block will be (g=10m/s
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Force on block = 40N
Force on block by friction = -0.2N
Therefore, total force = 40-0.2
= 39.98N
Therefore, acceleration of block = F/m
= 39.98/5
= 7.996m/s
This is my answer
Hope it helps!
(If it did help , please mark my answer as brainliest)
Force on block by friction = -0.2N
Therefore, total force = 40-0.2
= 39.98N
Therefore, acceleration of block = F/m
= 39.98/5
= 7.996m/s
This is my answer
Hope it helps!
(If it did help , please mark my answer as brainliest)
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