Physics, asked by hemanthrajkoti222, 1 year ago


A block of mass m slides down along the
surface of the bowl of radiusr from the rim to
the bottom. The velocity of the block at the
bottom will be​

Answers

Answered by eknathabadiger65
1

Answer:

Applying work kinetic energy theorem on the block for the time interval t=0 to t=tₒ, Here h is the vertical height between the initial and final horizontal levels of the particle. If the bowl is hemispherical then obviously h=R; the radius of hemisphere and v=√(2gR).

Similar questions