A block of size 20 m x 10 m x 5 m exerts a force of 30 N. Calculate the maximum & minimum pressure exerted by block on ground?
Answers
Answered by
339
We know, when force is constant, pressure ∞ 1/Area.
Therefore, pressure is maximum when area is minimum and vice versa.
By calculating the area of three faces, we get,
⇒A₁ = (20×10)= 200 sq m.
⇒A₂ = (10×5) = 50 sq m.
⇒A₃ = (20×5) = 100 sq m.
∴A₁ is maximum and A₂ is minimum.
∴Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².
∴Maximum pressure P₂ = F/A₂ = 30/50 = 0.6 Nm⁻². (Ans)
ALL THE BEST. :)
Therefore, pressure is maximum when area is minimum and vice versa.
By calculating the area of three faces, we get,
⇒A₁ = (20×10)= 200 sq m.
⇒A₂ = (10×5) = 50 sq m.
⇒A₃ = (20×5) = 100 sq m.
∴A₁ is maximum and A₂ is minimum.
∴Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².
∴Maximum pressure P₂ = F/A₂ = 30/50 = 0.6 Nm⁻². (Ans)
ALL THE BEST. :)
Answered by
23
Answer:
⇒A₂ = (10×5) = 50 sq m. ⇒A₃ = (20×5) = 100 sq m. ∴A₁ is maximum and A₂ is minimum. ∴Minimum pressure P₁ = F/A₁ = 30/200 = 0.15 Nm⁻².
Similar questions