Question

A block slides down an inclined plane of 30 degree with an acceleration equal to g upon you find the coefficient of kinetic friction

Answer 1

Given :Inclination angle=θ=30 degreesa=g/4 m/s²Coefficient of Kinetic friction .

Total net force= mg/4=mgsinθ-μmgcosθ

where μ is coefficient of kinetic friction.

mg/4=mg[sinθ-μcosθ]

[sinθ-μcosθ] =1/4

Substituting the inclination angle, we get

sin30- μcos30=1/4

1/2-μ√3/2=1/4

1/2-1/4=μ√3/2

2-1/4=μ√3/2

1/4=μ√3/2

μ=1/√3/2

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Answer 2

May this help you

Thank You

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