Question

A block slides on a vertical curved track of radius R = 1 m.If the speed of the block at point A is 2 m/s then the normal force exerted by the block on the track at A is

Answer 1

Given :

The radius of curved track = r = 1 meters

The speed of block at point A = v = 2 m/s

To Find :

The normal force exerted by the block on the track at A

Solution :

Let the mass of the block = M kg

The force exerted towards normal on circular path = F = $\dfrac{mass \times (velocity)^{2}}{radius}$

i.e   F = $\dfrac{M\times (v)^{2}}{r}$

         =  $\dfrac{M \times (2 m/s)^{2}}{1 m}$

         = 4 M  Newton

∴ Force = 4 M  Newton

Hence, The  normal force exerted by the block on the track at A is 4 M  Newton  . Answer

Answer 2

Answer:

28N

Explanation:

N-mg = (m×v^2)/r

N-2×10 = (2×{2×2})/1

N-20 = 8

N = 28N