Question

A block weighing 20 N is lifted 6 m vertically upward. Calculate the potential energy stored in it.
1 3.33 J
2 124 J
3 72 J
4 120 J

Answer 1

$\bigstar$ Given

A block weighing 20 N is lifted 6 m vertically upward

$\bigstar$ To Find

Potential energy stored in it

$\bigstar$ Solution

We know that

$\blue{\rm \longrightarrow F=m \times g}$

$\green{\rm \longrightarrow U=m \times g \times h}$

Hence

$\red{\rm \longrightarrow U=F \times h}$

Here

U = Potential Energy

F = Force

h = Height

Units

U = Joule (J)

F = Newton (N)

h = metre (m)

According to the question

We are asked to find potential energy stored in it

Therefore

We must find "U"

Given that

A block weighing 20 N is lifted 6 m vertically upward

Hence

F = 20 N

h = 6 m

Substituting the values

We get

$\orange{\rm \longrightarrow U=20 \times 6 \ J}$

Therefore

$\pink{\rm \longrightarrow U=120 \ J}$

Hence

Potential energy stored in it = 120 J

Therefore

$\checkmark$ Option (4) is correct

Answer 2

Explanation:

P = MGH

= 20 × 6

= 120J.....