A boat can travel 24 miles downstream in 2 hours and can make the return trip in 3 hours so what is the speed of the boat in still water and the speed of the current?
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let speed of boat in still water be = x km/k
let speed of boat in stream be = y km/h
therefore, in downstream speed = (x+y) km/h
while return boat will travel upstream so speed of boat in upstream = (x-y) km/h
now time=distance/speed
- while traveling downstream speed of boat = 2= 24/x+y ...............eq(1)
- while in upstream speed = 3= 24/x-y ............. eq(2)
eq (1) = 2=24/x+y
2x+2y=24 ....................(eq 3)
x+y=12...........................(taking 2 as common)
taking eq (2) 3=24/x-y
3x-3y=24 ..................(eq 4)
x-y=8......................................(taking 3 as common)
solving equation (3) we get
x+y=12
x=12-y.......................(eq 5)
put eqation 5 in eq (4)
x-y=8
(12-y)-y=8
-2y=8-12
-2y=-4
y=2
put value of y in equation 5
x=12-y
x=12-2
x=10
so speed of boat in still water is 10 km/h
and in current is 2 km/h
raghavsdoshioyijt7:
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