Math, asked by vrajkshah04cr7, 3 months ago

A boatman rows his boat 35 km upstream and 55 km downstream in 12 hours. He can row
30 km upstream and 44 km downstream in 10 hours. Find the speed of the stream and that of
the boat in still water. Hence, find the total time taken by the boatman to row 50 km upstream
and 77 km downstream.​

Answers

Answered by vaishnavichauhan90
1

This is Your answer !

Hope this will help

Attachments:
Answered by jayadythm01
3

Answer:

Step-by-step explanation:

Let the speed of the boat

in still water = x kmph

Speed of the stream = y kmph

i ) relative speed of the

boat in downstream

= ( x + y ) kmph

Distance travelled = d1 = 36

Time = t1 hr

t1 = d1 / s1

t1 = 36/ ( x + y )

ii) relative speed of the boat

in upstream = ( x - y ) kmph

Distancw = d2 = 32 km

Time = t2

t2 = 32/ ( x - y )

Therefore ,

Total time = 7 hr

t1 + t2 = 7hr

36 / ( x + y ) + 32/ ( x - y ) = 7 ----( 1 )

iii) second time ,

Relativespeed of the boat in

downstream = ( x + y ) kmph

d3 = 48 km

Time = t3

t3 = 48/ ( x + y )

iv ) in upstream

Relative speed of the boat = ( x - y )

kmph

time = t4 hr

d4 = 40km

t4 = 40/ ( x - y )

Total time = 9 hr

48 / ( x + y ) + 40/ ( x - y ) = 9 ---( 2 )

Let 1 / ( x + y ) = a ,

1 / ( x - y ) = b

Then rewrite ( 1 ) and ( 2 ) we get

36 a + 32 b = 7 -----( 3 )

48a + 40b = 9 ------( 4 )

Multiply ( 4 ) with 4 and equation ( 3 ) with 5 and

192a + 160b = 36 ---( 5 )

180a + 160b = 35 -----( 6 )

Subtract ( 6 ) from ( 5 )

we get

a = 1/ 12

put a = 1/ 12 in ( 3 )

we get ,

b = 1/ 8

Now 1/ ( x + y ) = 1/ 12

1/ ( x - y ) = 1/ 8

Therefore ,

x + y = 12 ----( 7 )

x - y = 8 ----- ( 8 )

add ( 7 ) and ( 8 )

2x = 20

x = 10

put x = 10 in ( 7 ) we get

y = 2

Speed of the boat in

still water = x = 10 kmph

speed of the stream

= y = 2kmph

I hope this helps you.

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