Question

In the above figure a constant current 1 ampure is flowing through 5 omh resistance What is the current through R1 and R2 What is the P. D across AB and AC​

Answer 1

Given,

Current in AC, IAC=1A

 Resistance in BC, RBC=10+1510×15=6Ω

Current flowing in series  IAB=IBC=1A

VBC=IBC×RBC=1×6=6V

In parallel potential is equal

VBC=I10R10=I15R15=6

(a)    I10=106=0.6A,  I15=150.6=0.4A

(b)    Potential in AB VAB=IABRAB=1×5=5V., VBC=IBC