Question

A body 'A' of mass 10 kg moving with a velocityr 5 m/s impinges directly on another body 'B' of mass 20kg at rest. it after impact 'A' comes to resi, calcult the vilocity of 'B

Answer 1

m1=10 kg m2=20kg
u1=5m/s u2=0
v1=0 v2=?
according to law of conservation of mass
m1u1+ m2u2=m1v1+m2v2
10kgx5m/s+20kgx0=10kgx0+20kgx v2
50kg m/'s +0=0+ 20kg x v2
v2= 50kg m/'s ÷ 20kg
v2=2.5m/'s


hope it helps you