Question

A body accelerates uniformly from rest at the rest of 3m/square for 8seconds .Calculate the distance covered by the body during acceleration

Answer 1

Answer:

The body will move 192 m (200 m rounded to one significant figure).

Explanation:

d = vᵢt + 1/2at² ; where d = distance, vᵢ = initial velocity, a = acceleration, and t = time interval

Since vᵢ = 0, vᵢt = 0, the formula can be rewritten as:

d = 1/2at²

Data

d = ? m

a = 3 m/s²

t = 8 s

Calculation

d = 3 m/s² × (8 s)²

d = 3 m/s² × 64 s²

d = 192