a body dropped from a height of 49 m find the time taken by the body to reach ground
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Given :
Height =h =49m
Initial speed= u= 0 m/s as dropped from height.
time =t=?
a=g=9.8m/s²
From the second equation of motion :
s=ut+1/2at²
49=0xt +1/2*9.8*t²
49=4.9 t²
t²=49/4.9
=490/49
t²=10sec
t=√10 sec=3.16 sec
∴ Time taken by the body to reach the ground is 3.16sec
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Anonymous:
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Answer:
Sorry iam radiographer i mean iam x ray tech
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