A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s^2)
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let the total height be =h
so according to second law of motion
h=1/2gt²
=5t².......(1)
remaining s=h-40
remaing time=t-2
so...h-40=1/2g(t-1)²
5t²-40=5t²+20-20t
this givest=3sec
put this value in (1)
we get..h=45m
so according to second law of motion
h=1/2gt²
=5t².......(1)
remaining s=h-40
remaing time=t-2
so...h-40=1/2g(t-1)²
5t²-40=5t²+20-20t
this givest=3sec
put this value in (1)
we get..h=45m
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