Question

A body falls from a height h = 200 m. The ratio of distance travelled in each 2 s, during t=0 to
t = 6 s of the journey is
(1) 1:4:9
(2) 1 : 2:4
(3) 1 : 3:5
(4) 1:2:3​

Answer 1

Answer:

ans:(3)

Explanation:

distance travelled in first 2s = 1/2gt²

= 1/2(10)(2)² — 1

= 20m

distance travelled in first 4s = 1/2gt²

= 1/2(10)(4)² — 2

= 80m

distance travelled in first 6s = 1/2gt²

= 1/2(10)(6)² — 3

= 180m

so, ratio of distances travelled by the body in equal time intervals i.e. in every 2s is...

= (20m) : (80–20m) : (180–80m)

= (20m) : (60m) : (100m)

= 1:3:5