Question

A body falls from height of 500 m. In how much time will it strike the ground ?

Answer 1

Answer:

10 seconds

Explanation:

from the question

given that body falls so u=0 [initial velocity]

                 free fall so acceleration = g = 10 m/s^2

                    distance = 500m

use formula s=ut+1/2 at^2

   500 = 0 + 1/2 * 10*t^2

  so t^2 = 100

then t= 10 seconds

hope it helps

Answer 2

Answer:

Let acceleration = 10m/s^2

Distance is 500m

Initial velocity 0m/s

S= ut+1/2at^2

500= 0+1/2 ×10 (t)^2

(t)^2 = 500/5

= 100m

t= 10 sec

Please mark me as branliest

Explanation: