A body has weight 50 kg on earth surface on which height it's weight remains 25 kg
prakhargupta3301:
tell me if its weight or mass
then only sol is possible. mass (kg) never changes universally
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Weight (formerly)= F=ma⇒(50*10)= 500 N (taking g=10ms-2 for convenience)
Weight is 25 N finally
F=ma
25N=50kg.g₂ (let g₂ be final acceleration due to gravity)
25/50= g₂
1/2= g₂
0.5=g₂
g=GMm/R² (M=m1 (mass of earth, m=m2(mass of object). G= Gravitational constant=6.674 × 10⁻¹¹ m³ kg⁻¹ s⁻²)
0.5= {G ×6*10²⁴kg × 50kg } ÷ (R)² (R we have to find)
R²= G*6*10²⁴kg *50kg ÷ 0.5 ms⁻²
R²= G* 6* 10²⁶ kg²s²m⁻¹
R²= 6.674 × 10⁻¹¹ m³ kg⁻¹ s⁻² ×6* 10²⁶ kg²s²m⁻¹
R²= 40.044*10¹⁶
R=6.32*10⁶ metres
I know this is wrong but i took g=10 previously. check with 9.8
Weight is 25 N finally
F=ma
25N=50kg.g₂ (let g₂ be final acceleration due to gravity)
25/50= g₂
1/2= g₂
0.5=g₂
g=GMm/R² (M=m1 (mass of earth, m=m2(mass of object). G= Gravitational constant=6.674 × 10⁻¹¹ m³ kg⁻¹ s⁻²)
0.5= {G ×6*10²⁴kg × 50kg } ÷ (R)² (R we have to find)
R²= G*6*10²⁴kg *50kg ÷ 0.5 ms⁻²
R²= G* 6* 10²⁶ kg²s²m⁻¹
R²= 6.674 × 10⁻¹¹ m³ kg⁻¹ s⁻² ×6* 10²⁶ kg²s²m⁻¹
R²= 40.044*10¹⁶
R=6.32*10⁶ metres
I know this is wrong but i took g=10 previously. check with 9.8
if it was 25 newton thn it was possible
but here it is 25kg. so for that we need g
which is not given
ok it was 25 N
comone really
srsly
now u tell me
are u sure final weight is 25 Newton?
yes
ok wait
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