a body having an initial velocity of 3m/s is subjected to an acceleration of 5m/s after 5s . calculate it's final velocity
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Answered by
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we know that,
a= v-u/t
so we put all given.
5=v-3/5. (v is not given)
so, v=25+3=28 m/s
thank you.
a= v-u/t
so we put all given.
5=v-3/5. (v is not given)
so, v=25+3=28 m/s
thank you.
Answered by
0
Hi there,
Given data -
u = 3m/s
a = 5m/so
v = ?
t = 5s
Formula used -
v = u + at
v = 3 + 5×5
v = 3 + 25
v = 28m/s
Thanks:)
Given data -
u = 3m/s
a = 5m/so
v = ?
t = 5s
Formula used -
v = u + at
v = 3 + 5×5
v = 3 + 25
v = 28m/s
Thanks:)
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