Physics, asked by Anonymous, 9 months ago

A body in motion covers distance of 5mm in 1mew sec.find it's velocity​

Answers

Answered by Anonymous
2

Explanation:

The distance covered in n

th

second,

S

n

=u+

2

a

(2n−1) . . . . . . . . . . .(1)

For n=3 and S

3

S

3

=u+

2

a

(6−1)=10

10=u+

2

5a

. . . . . . . . .(2)

For n=4 and S

4

=12m

S

4

=u+

2

a

(8−1)

12=u+

2

7a

. . . . . . . . .(3)

Subtract equation (3) by equation (2),

12−10=(u+

2

7a

)−(u+

2

5a

)

a=2m/s

2

From equation (2),

10=u+

2

5×2

10=u+5

u=5m/s

The correct option is D.

Answered by Saurav356
0

Answer:

answer is 5 millimetres per microsecond.

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