Question

A body initially at rest travels a distance 10 m in 2 sec with constant acceleration. Calculate : - Acceleration​

Answer 1

Answer:

Given :-

• A body initially at rest travels a distance of 10 m in 2 seconds with constant acceleration.

To Find :-

• What is the acceleration.

Formula Used :-

$\clubsuit$ Second Equation Of Motion Formula :

$\longrightarrow \sf\boxed{\bold{\pink{s =\: ut + \dfrac{1}{2} at^2}}}$

where,

• s = Distance Covered
• u = Initial Velocity
• t = Time Taken
• a = Acceleration

Solution :-

Given :

• Distance Covered = 10 m
• Initial Velocity = 0 m/s
• Time = 2 seconds

According to the question by using the formula we get,

$\leadsto \sf 100 =\: (0)(2) + \dfrac{1}{2} \times a \times (2)^2$

$\leadsto \sf 100 =\: 0 \times 2 + \dfrac{1}{2} \times a \times (2 \times 2)$

$\leadsto \sf 100 =\: 0 + \dfrac{1}{2} \times a \times 4$

$\leadsto \sf 100 =\: 0 + \dfrac{1}{\cancel{2}} \times {\cancel{4}}a$

$\leadsto \sf 100 =\: 2a$

$\leadsto \sf \dfrac{100}{2} =\: a$

$\leadsto \sf 50 =\: a$

$\leadsto \sf\bold{\red{a =\: 50\: m/s^2}}$

$\therefore$ The acceleration of a body is 50 m/s² .