Question

a body initially at rest travels a distance of 100m in 5s with a constant acceleration. calculate the acceleration and the final velocity at end of 5s

Answer 1

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Answer 2

Answer:

given- d=100

t =5s

to find = acceleration and the final velocity at end of 5s

STEP1:

distance (s) = 100m , initial velocity (u) = 0 , time (t) = 5

here acceleration is constant so equations of motion can be used

Step using third equation of motion

s = ut + at^2 /2

here s is distance, u is initial velocity, a is acceleration, t is time

100 = 0(5) + a(5^2)/ 2

100 = 0 + 25a /2

100×2 = 25a

a = 8m/s^2

Step3:

here in second case time is given, acceleration is there and initial velocity is also given

so 1st equation of motion can be applied

Step 4

v = u +at

where v is final velocity , u is initial velocity , a is acceleration and t is time

v = 0 + 8(5)

v = 40m/s

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