A.Body is dropped drom.A.Balloon moving up/with a velocity of 4ms when the balloon is at height 120.5 m from ground .The separation between the body and balloon after 8 sec is
Answers
Answered by
3
the initial velocity of ballon =4ms
acceleration=9.8m/s^2
time =8sec
apply the formula –. s=ut+1/2gt^2
then surely you get the answer apply all data with proper sign
MARK ME as brainliest
acceleration=9.8m/s^2
time =8sec
apply the formula –. s=ut+1/2gt^2
then surely you get the answer apply all data with proper sign
MARK ME as brainliest
Answered by
3
Answer:
............................
Attachments:
Similar questions