Question

A body is dropped from a height of 30m . what is the velocity pf the body after it has covered a distance of 29m ? given g= 10m/s2​

Answer 1

☃️$\huge{\underbrace{\pink{ans{\orange{wer}}}}}$☃️

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’.

Given parameters

Initial Velocity of the ball (u) = 0

Distance or height of fall (s) = 20 m

Downward acceleration (a) = 10 m s-2

As we know

2as = v2 – u2

v2 = 2as + u2

v2 = (2 x 10 x 20 ) + 0

v2 = 400

Final velocity of ball (v) = 20 ms-1

t = (v – u)/a

Time taken by the ball to strike (t) = (20 – 0)/10

t = 20/10

t = 2 seconds

The final velocity with which ball will strike the ground is (v) = 20 ms-1

The time it takes to strike the ground (t) = 2 seconds.

⠀

⠀

⠀

⠀

Ye dekho iss Hitesh ki harkat ‍♀️

Answer mein kya kya post kar rha h....... xD

But bhai mein aapko sahi answer dungi...xD

isliye.....¯\_(ツ)_/¯

Please mark Brainliest ❤️