A body is dropped from a height of 320m. The acceleration due to gravity is 10m/sec^2. (a) How long does it take to reach the ground. (b) What is the velocity with which it will strike the ground .
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b) Applying v^2-u^2=2aS we get v^2-0^2=2×10×320
=v^2-0=6400
so v=80
a) applying v=u+at we get
80=0+10t
10t=80
t=8
mark me brainliest if possible
=v^2-0=6400
so v=80
a) applying v=u+at we get
80=0+10t
10t=80
t=8
mark me brainliest if possible
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