Question

A body is dropped from the roof of a building 10 metre high calculate the time of fall and the speed with which it hit the ground at. Take gram is equal to 10 metre per second square.
answer ur own don't copy​

Answer 1

Free fall of a body ,

V^2 = 2gh

V^2 = 2 (10) (10)

V^2 = 200

V = 10 root 2 m/s

V = 14.1 m/s ( since root 2 = 1.41

so now the time will be

V = U + gt

14.1 = 0 + 10 (t)

so now here ,

t = 1.41 seconds

Answer 2

Answer :-

Given,
S = 10 m
g = 10 m per second
u = 0m/s

We know,

${v}^{2} = {u}^{2} + 2gs \\ \\ {v}^{2} = {0}^{2} + 2 \times 10 \times 10 \\ \\ {v}^{2} = 200 \\ \\ v = \sqrt{200} \\ \\ v = 14.14 \: m {s}^{ - 1}$


Again,

$v = u + gt \\ \\ 14.14 = 0 \times 10 \times t \\ \\ t = \frac{14.14}{10} \\ \\ t = 1.414 \: s$


Thanks!!