Question

A body is dropped from the top of a tower. It acquires a velocity 20 ms⁻¹ on reaching the ground. Calculate the height of tower. (g = 10 ms⁻²)

Answer 1

Height of the tower = 20 metres

Explanation:

A body is dropped from the top of a tower. It acquires a velocity 20 ms⁻¹ on reaching the ground.

g = 10 ms⁻²

For a free falling body, initial velocity u = 0

final velocity v = 20 ms⁻¹

v^2 = u^2 + 2as

20*20 = 0 + 2 * 10 *s

s = 400 / 20 = 20 m

Height of the tower = 20 metres.