Math, asked by IFSShashankKamal, 7 months ago

A body is dropped from the top of a tower. It acquires a velocity of 20 m/s on reaching the ground. Calculate the height of the tower. (Take g = 10 m/s2)

Answers

Answered by Anonymous

Final velocity , v=20m/s

g=10m/s

2 By third eqation of motion we have,

v

2 =u

2 +2gS

Since, u=0

S=

2g

v

2 ⇒S=

2×10

20

2 =20m

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A body is dropped from the top of a tower. It acquires a velocity of 20 m/s on reaching the ground. Calculate the height of the tower. (Take g = 10 m/s2)​

Answers

Final velocity , v=20m/s

g=10m/s

2

By third eqation of motion we have,

v

2

=u

2

+2gS

Since, u=0

S=

2g

v

2

⇒S=

2×10

20

2

=20m

A body is dropped from the top of a tower. It acquires a velocity of 20 m/s on reaching the ground. Calculate the height of the tower. (Take g = 10 m/s2)