A body is dropped from the top of a tower. It acquires a velocity of 20 m/s on reaching the ground. Calculate the height of the tower. (Take g = 10 m/s2)
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Final velocity , v=20m/s
g=10m/s
2
By third eqation of motion we have,
v
2
=u
2
+2gS
Since, u=0
S=
2g
v
2
⇒S=
2×10
20
2
=20m
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