A body is projected at such an angle that the horizontal range is three times the greatest height find the angle of projection
Answers
Answered by
113
Formula = H / R = tan theta / 4
So tan theta = 4/3
Theta = arc sin (4/5)
So tan theta = 4/3
Theta = arc sin (4/5)
kvnmurty:
Click on the thanks button above please
Answered by
185
we know ,
horizontal range = u²sin2Ф/g
maximum height = u²sin²Ф/2g
A/C to question,
horizontal range = 3× maximum height
u²sin2Ф/g = 3 × u² sin²Ф/2g
{ sin2Ф = 2sinФ.cosФ }
2sinФ.cosФ = 3/2. sin²Ф
tanФ = 4/3
Ф = tan⁻¹(4/3)
horizontal range = u²sin2Ф/g
maximum height = u²sin²Ф/2g
A/C to question,
horizontal range = 3× maximum height
u²sin2Ф/g = 3 × u² sin²Ф/2g
{ sin2Ф = 2sinФ.cosФ }
2sinФ.cosФ = 3/2. sin²Ф
tanФ = 4/3
Ф = tan⁻¹(4/3)
Similar questions