A body is projected horizontally with speed 20 m per second what will be its speed after 5 seconds
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Since, body is projected horizontally with a velocity of 20m/s.
ux = 20m/s
ax = 0
So, vx = 20m/s for all time.
Along vertical axis,
uy = 0
t = 5
ay = 10m/s2
vy =?
vy = uy +ayt
=> vy = 0 + 10*5= 50m/s
So, magnitude of velocity of body after 5s
√{(50)²+(20)²}m/s
=√2900 m/s
=53.851 m/s
= 54 m/s (approx)
ux = 20m/s
ax = 0
So, vx = 20m/s for all time.
Along vertical axis,
uy = 0
t = 5
ay = 10m/s2
vy =?
vy = uy +ayt
=> vy = 0 + 10*5= 50m/s
So, magnitude of velocity of body after 5s
√{(50)²+(20)²}m/s
=√2900 m/s
=53.851 m/s
= 54 m/s (approx)
Answered by
0
Ah kinematics. That takes me back. If the body is not far off the ground, the answer is zero.
But if it filled with helium, the answer is a little ways in the wind direction and mainly straight up but undetermined.
But seriously, you shouldn't be digging up bodies and throwing them around to test the laws of gravity.
But if it filled with helium, the answer is a little ways in the wind direction and mainly straight up but undetermined.
But seriously, you shouldn't be digging up bodies and throwing them around to test the laws of gravity.
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