A body is projected horizontally with speed 20m/s .what will be its speed after 5 seconds ?
Answers
Answered by
15
Initial speed u=20m/s
As it is horizontally projected all the speed is as x-component.
Since there is no force in x-direction, the speed shall remain constant.
After 5sec, speed in y-axis will be,
v=0+(10)5
v=50m/s
So velocity of body will be 20i-50j
Speed will be 10√29m/s
As it is horizontally projected all the speed is as x-component.
Since there is no force in x-direction, the speed shall remain constant.
After 5sec, speed in y-axis will be,
v=0+(10)5
v=50m/s
So velocity of body will be 20i-50j
Speed will be 10√29m/s
Answered by
4
Hii frnds...
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u = 20 m/s
acceleration= -10m/s^2
time = 5 s
v= u + at
= 20+ -10×5
= 20 - 50
= -30 m/s
therefore object will fall down (as final speed is in negative) towards the throwing point.
v = 30 m/s ( in downward direction)
your answer is
___________________________________
hope it helps u. :))
___________________________________
u = 20 m/s
acceleration= -10m/s^2
time = 5 s
v= u + at
= 20+ -10×5
= 20 - 50
= -30 m/s
therefore object will fall down (as final speed is in negative) towards the throwing point.
v = 30 m/s ( in downward direction)
your answer is
___________________________________
hope it helps u. :))
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