A body is projected vertically upwards with a velocity of 19.6 m/s reaches a height of 19.8 m on earth. If it is projected vertically up with the same velocity on moon, then the maximum height reached by it is
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Answered by
34
Hi friend
we will be using formula
v2 =u2 + 2gs
where v is final velocity u is initial velocity g is gravitational acceleration and s is the height
substituting values
02 = 19.6 * 19.6 + 2 * 1.6 * s.........(as gravitational acceleration on moon is 1.6m/s2
0 = 384.16 + 3.8s
therefore
s = 384.16 / 3.8
s = 101m
hence maximum height reached by the object is 2m on moon
HOPE THIS HELPS
PLZZZZZ MARK BRAINLIEST
we will be using formula
v2 =u2 + 2gs
where v is final velocity u is initial velocity g is gravitational acceleration and s is the height
substituting values
02 = 19.6 * 19.6 + 2 * 1.6 * s.........(as gravitational acceleration on moon is 1.6m/s2
0 = 384.16 + 3.8s
therefore
s = 384.16 / 3.8
s = 101m
hence maximum height reached by the object is 2m on moon
HOPE THIS HELPS
PLZZZZZ MARK BRAINLIEST
Answered by
34
Hi Friend
______________________________________________________________
velocity on earth = 19.6 m/s
height = 19.8 m
______________________________________________________________
v^2- u^2 = 2 a s
(19.6 )^2 = 2 x a x 19.8
384.16 /19.8 = 2 x a
19.4 = 2 a
a = 19.4/2
a = 9.7 m s^-2
so the acceleration due to gravity is 9.7 on earth
___________________________________________________________
On moon :
v^2-u^2 = 2as
(19.6 )^2 = 2 x 9.7/6 x s
384.16 = 2 x 1.61 x s
384.16 = 3.23 x s
384.16/3.23 = s
118.93 m = s
______________________________________________________________
velocity on earth = 19.6 m/s
height = 19.8 m
______________________________________________________________
v^2- u^2 = 2 a s
(19.6 )^2 = 2 x a x 19.8
384.16 /19.8 = 2 x a
19.4 = 2 a
a = 19.4/2
a = 9.7 m s^-2
so the acceleration due to gravity is 9.7 on earth
___________________________________________________________
On moon :
v^2-u^2 = 2as
(19.6 )^2 = 2 x 9.7/6 x s
384.16 = 2 x 1.61 x s
384.16 = 3.23 x s
384.16/3.23 = s
118.93 m = s
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