Question

a body is projected with velocity 20√3 with angle of projection 60° with horizontal calculate velocity on that pont where body make 30° angle with horizontal​

Answer 1

Answer:

See below.

Explanation:

A body is projected with velocity 20(root3) with the angle of projection equal to 60 degrees.

$u = 20 \sqrt{3} \\\theta = 60^{\circ}$

Along the horizontal direction, there is no acceleration, therefore the horizontal velocity remains constant throughout the trajectory of the projectile.

$v_x = u \cos \theta = ( 20 \sqrt{3} ) \times \cos( 60^{\circ} ) = 10 \sqrt{3}$

Answer 2

the velocity of that point is 20m/s