Physics, asked by anuarya272, 5 months ago

A body is thrown up with a velocity 50m/s calculate the maximum height reached and the time taken to reach the maximum height (a=10m/s​

Answers

Answered by hero6653
7

Given

velocity (v) = 50 m/s

acceleration = 10 m/s

Required formulas

acceleration = velocity / time

velocity = displacement / time

Answer

 acceleration =  \frac{velocity}{time}

10 =  \frac{50}{t}

hence  \\ t =  \frac{50}{10}

hence the time required is 5 seconds

Now

velocity =  \frac{displacement}{time}

Here, displacement is the distance travelled

hence

50 =  \frac{s}{5}

hence

{displacement}  = 5  \times 50

hence

the maximum distance travelled by the object is 250 m

hence your answer should be 250 meter

I hope this answer is helpful to you

if it is then like it and rate it

and follow me plz

Answered by farhanfarhanfarad
0

Answer:

What is the initial velocity

Similar questions