a body is thrown up with a velocity of 20m/s . it retards uniformly at the rate of 10m/s .find the velocutyof the body after 2 seconds?
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Answered by
4
Given
u=20 m/s
a=10 m/s
t=2 sec
v=u-at {negative sign because of retarfation}
Or, v=20-10×2
Or, v=0m/s.
The velocity after 2 sec will be 0 m/s that is it will come to a stop.
Hope this helps.
u=20 m/s
a=10 m/s
t=2 sec
v=u-at {negative sign because of retarfation}
Or, v=20-10×2
Or, v=0m/s.
The velocity after 2 sec will be 0 m/s that is it will come to a stop.
Hope this helps.
Answered by
0
Answer:
Initial velocity = 20 m/s
Acceleration = 10 m/s
Time = 2sec
V = u - at
=> V = 20 - 10 × 2
=> V = 0 m/s
The velocity of the body after 2 seconds is 0 m/s.
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