A body is thrown up with velocity of 40m/s. How long does it take to reach the highest point? After how much time will the body come back to ground?
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Answered by
14
Let us take g= 10N/m^2
distance = u^2/2g
= 40×40÷2×10
= 1600÷20
= 80
Therefore, It takes 80m to reach highest point
Time taken. = 2u÷g
= 2×40÷10
= 80÷10
= 8sec
The total time taken = 8sec
distance = u^2/2g
= 40×40÷2×10
= 1600÷20
= 80
Therefore, It takes 80m to reach highest point
Time taken. = 2u÷g
= 2×40÷10
= 80÷10
= 8sec
The total time taken = 8sec
Answered by
3
here is the answer is yes
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