A ladder is placed in such a way that its foot is at a distance of 8m from a wall and its top reaches a window 6m above the ground. What is the length of the ladder
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GIVEN
DISTANCE BETWEEN WALL AND ITS FOOT IS 8 m
WINDOW HEIGHT FROM GROUND IS 6 m
LET THE LENGTH OF LADDER BE X,
TO FIND LENGTH OF LADDER ,WE WILL USE PHYTHAGORAS THEOREM METHOD.
BASE=DISTANCE BETWEEN WALL AND ITS FOOT
HEIGHT=WINDOW HEIVHT
SO X= Square root of X^2
X^2=(BASE+HEIGHT)
X^2=(8^2+6^2)m
X^2=(64+36)m
X^×=100m
SO, X^2=100m
NOW,
X=SQUARE ROOT OF 100m
X=10m
SO, LENGTH OF LADDER EQUAL TO 10m
PLEASE MARK MY ANSWER AS BRAINLIEST. BEACAUSE I HAVE TAKEN A LOT OF TIME OF MINE TO ANSWER YOUR QUESTION.
DISTANCE BETWEEN WALL AND ITS FOOT IS 8 m
WINDOW HEIGHT FROM GROUND IS 6 m
LET THE LENGTH OF LADDER BE X,
TO FIND LENGTH OF LADDER ,WE WILL USE PHYTHAGORAS THEOREM METHOD.
BASE=DISTANCE BETWEEN WALL AND ITS FOOT
HEIGHT=WINDOW HEIVHT
SO X= Square root of X^2
X^2=(BASE+HEIGHT)
X^2=(8^2+6^2)m
X^2=(64+36)m
X^×=100m
SO, X^2=100m
NOW,
X=SQUARE ROOT OF 100m
X=10m
SO, LENGTH OF LADDER EQUAL TO 10m
PLEASE MARK MY ANSWER AS BRAINLIEST. BEACAUSE I HAVE TAKEN A LOT OF TIME OF MINE TO ANSWER YOUR QUESTION.
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