A body is thrown upwards with a velocity of 20 m/s. How much time will it take to return to its original position?
Answers
Answered by
93
Given,
u = 20 m/s
v =0
t = time of descent + time of ascent
a = g
(while going up)
v =u + at
0= 20-9.8 t
20=9.8 t
t = 2.0
(while reaching the ground)
v = u + at
v = gt
20=9.8 t
t ≈2 seconds
Hence time of flight =4 seconds.
it will take 4 seconds to return to its original position.
u = 20 m/s
v =0
t = time of descent + time of ascent
a = g
(while going up)
v =u + at
0= 20-9.8 t
20=9.8 t
t = 2.0
(while reaching the ground)
v = u + at
v = gt
20=9.8 t
t ≈2 seconds
Hence time of flight =4 seconds.
it will take 4 seconds to return to its original position.
Answered by
15
Answer:
4second
Explanation:
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