A body is thrown upwards with an initial velocity of 12m\s
How far does it go during the first second
Find the maximum height it reaches
How long does it remain in air
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acceleration of a body at all points during it's vertical motion will be g downwards.
By equation of motion
S = ut+ 1/2 at^2
=ut-1/2gt^2
=12×1 -1/2 ×10 ×1
=12 - 5
=7m
Distance travelled in 1st second =7m
H = u^2/2g
=(12)^2/20
=144/20
=7.2m
Time of flight = 2u/g
=2÷12/10
=2.4s
Hope this helps.
✌
By equation of motion
S = ut+ 1/2 at^2
=ut-1/2gt^2
=12×1 -1/2 ×10 ×1
=12 - 5
=7m
Distance travelled in 1st second =7m
H = u^2/2g
=(12)^2/20
=144/20
=7.2m
Time of flight = 2u/g
=2÷12/10
=2.4s
Hope this helps.
✌
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