a body is thrown vertically downward and takes 5 sec to reach max height . the distance travelled by the body will be same in?
a. 1st nd 10th sec
b. 2nd nd 8th sec
c. 4th nd 6th sec
d.both a nd c
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Body reach at maximum height after 5 sec then v = u−gt ⇒ 0 = u − g×5 ⇒ u =50m/s2 Distance travelled by the body in 1st sec = distance travelled in t =1s - distance travelled in t=0s ⇒ h =ut − 12gt2 = 45m (up) Distance travelled by the body in 10th sec = distance travelled in t =10s - distance travelled in t=9s ⇒h = ut +12gt2 = 45m (down) So, first option will be right
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