a body is thrown vertically upward with a velocity of 9.8 metre per second calculate the maximum height attained by the body is equal to 9.8 M per second square
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Answered by
96
Answer : 4.9 m is the height attained.
Step-by-step explanation :
Whenever a body is vertically thrown up then at some time it's final velocity (v) will be 0.
Since we know that,
⇒v² - u² = 2gs
Here, v = 0, u = 9.8 m/s and g = - 9.8 m/s² [ - ve because acceleration against gravity ]
⇒0² - 9.8² = 2(-9.8)s
⇒- 9.8 × 9.8 = - 2 × 9.8 × s
⇒- ( 9.8 × 9.8 ) / - ( 2 × 9.8 ) = s
⇒9.8/2 m = s
⇒4.9 m = s
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Plot the points Ona graph paper.Verify whether they lie on a line ?

Plot the points Ona graph paper.Verify whether they lie on a line ? a ) (1,1) ,(-3,-3), (4,4)(-4,-4). b) (1,2) ,(3,5)(4,3)(5,1)

Plot the points Ona graph paper.Verify whether they lie on a line ? a ) (1,1) ,(-3,-3), (4,4)(-4,-4). b) (1,2) ,(3,5)(4,3)(5,1)
Answered by
98
Answer : 4.9 m is the height attained.
Step-by-step explanation :
Whenever a body is vertically thrown up then at some time it's final velocity (v) will be 0.
Since we know that,
⇒v² - u² = 2gs
Here, v = 0, u = 9.8 m/s and g = - 9.8 m/s² [ - ve because acceleration against gravity ]
⇒0² - 9.8² = 2(-9.8)s
⇒- 9.8 × 9.8 = - 2 × 9.8 × s
⇒- ( 9.8 × 9.8 ) / - ( 2 × 9.8 ) = s
⇒9.8/2 m = s
⇒4.9 m = s
Step-by-step explanation :
Whenever a body is vertically thrown up then at some time it's final velocity (v) will be 0.
Since we know that,
⇒v² - u² = 2gs
Here, v = 0, u = 9.8 m/s and g = - 9.8 m/s² [ - ve because acceleration against gravity ]
⇒0² - 9.8² = 2(-9.8)s
⇒- 9.8 × 9.8 = - 2 × 9.8 × s
⇒- ( 9.8 × 9.8 ) / - ( 2 × 9.8 ) = s
⇒9.8/2 m = s
⇒4.9 m = s
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