Question

a body is thrown veticaly upwards with a velocity5m/s 1)how much time it will take to reach maximum height 2) which is the maximum height of body reaches

Answer 1

GIVEN:-

• $\rm{Initial\:Velocity=5m/s}$.

• $\rm{Final\:Velocity= 0m/s}$

• $\rm{Acceleration\:due\:to\:Gravity= -10m/s^2}$.

TO FIND:-

• The time taken by body to reach the maximum height.

• Mangnitude of Maximum height reached by body.

FORMULAE USED:-

• ${\huge{\boxed{\rm{V=u+at}}}}$

• ${\huge{\boxed{\rm{v^2-u^2=2as}}}}$.

Where,

v= Final Velocity

u= initial Velocity

a= Acceleration due to gravity

t= Time

S = Distance.

Now,

$\implies\rm{V= u+at}$

$\implies\rm{0=5-10t}$

$\implies\rm{-5=-10t}$

$\implies\rm{t=\dfrac{5}{10}}$

$\implies\rm{t=0.5s}$.

Again,

$\implies\rm{v^2-u^2=2as}$

$\implies\rm{(0)^2-(5)^2=2\times{-10}\times{s}}$

$\implies\rm{-25=-20s}$

$\implies\rm{s=\dfrac{25}{20}}$

$\implies\rm{S=1.25m}$.

Hence, The maximum height reached by ball is 1.25m in time interval of 0.5s.

• When body is falling freely we take Initial velocity as zero.

• When body is thrown upwards we take final velocity as zero.