Question

A body moves with v=10 m/s , s=50 m and the relation between s and t is as follows s=t^2 + 5t. find u and a. ​

Answer 1

50 = t^2 + 5t

t^2 + 5t - 50 = 0

t + 10 x t - 5 = 0

t = 5 sec ( time can't be negative)

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Answer 2

The correct option is A.

Given,

x=t ²−4t+6

So, the change in velocity is:

dt/dx =2t−4

Since velocity is changing,

At t=0,x1 =6

At t=2,x2 =2

So the magnitude of the distance traveled is:

6−2=4m

At t=3,x3 =3

So distance traveled from t=2s to t=3s

x³ −x² =3−2=1m

Thus the total distance is:

4+1=5m