A body moving with a constant acceleration travels the distance 3m and 8m respectively in 1s and 2s.Calculate : (i) the initial velocity, and (ii) the acceleration of body.
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d1 = 3 m
d2 = 8m
t1= 1s
t2= 2s
u = ?
a =?
Total distance = 3+8= 11 m
Total Time = 2+1 = 3 sec
Now
We know that ,
Speed( v) = distance / time
v = 11/3
v = 3.6 m/s
After this I don't know
Thank you
d2 = 8m
t1= 1s
t2= 2s
u = ?
a =?
Total distance = 3+8= 11 m
Total Time = 2+1 = 3 sec
Now
We know that ,
Speed( v) = distance / time
v = 11/3
v = 3.6 m/s
After this I don't know
Thank you
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