a body of 2 kg Falls from rest what will be its kinetic energy during the fall at the end of 2 seconds assume g
is equals to 10 metre per second square
Answers
Answered by
4
KE=1/2mv^2
=100 joules
=100 joules
Answered by
14
Mass is 2 kg
v = u+ at
v = 0 + 10 ×2
v= 20 ms^-1
SO kinetic energy = 1/2 × 20×20×2
Kinetic energy = 400 J
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v = u+ at
v = 0 + 10 ×2
v= 20 ms^-1
SO kinetic energy = 1/2 × 20×20×2
Kinetic energy = 400 J
Please mark it as brainliest answer
I request u
Please do it
My friend please mark it as brainliest answer
STORMSUNIL:
Please mark It as brainliest answer
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