Question

A body of mass 0.5 kg travels in a
straight line with velocity v = 5 x3/2.
The work done by the net force during
the displacement from x = 0 to x = 2
mis (in joule)​

Answer 1

Explanation:

the work done by the net force during.

Answer 2

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50 joules ✔

$\large \fbox \red{explaination : }$

Given:

Mass, m = 0.5 kg

veleocity, u= 5.x^(3/2) ,

Acceleration, a = 5 m/s^2 .

To find:

Work done (x = 0 to x = 2 m), W= ?

Solution:

☞ Initial velocity at x = 0,

v1 = 5 x 0 = 0

☞ Final velocity at x = 2,

v2 = 5(2)^ 3/2 

∴ Work done = increase in K.E

⇒W = 1/2 m{(v2)^2-(v1)^2}

⇒W = 1/2 x 0.5[(5 x (2)^ 3/2)^2 – 0]

⇒W = 50 J.

Hence, the required work done is 50 joules.

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