Question

the sum of the areas of two squares is 400m.sq.if the difference between thier perimeters is 16 m.find the sides of the squares ​

Answer 1

Answer:

let the side of first square = a

let the side of second square = b

so

$a^{2}$ + $b^{2}$ = 400 =>  (a + b)(a - b) = 400--------(1)

also

4a - 4b = 16

a - b = 4  ---------(2)

putting 2 in 1

(a + b) = 100--------(3)

solving from 1 and 2 we get

a = 52

b = 48

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