A body of mass 1 kg is projected from ground at an angle 30° with horizontal on a level ground at a speed
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remains constant so change in momentum is because of the vertical component of its velocity.
so, taking only vertical component
initial velocity = vsin300 [upwards]
final velocity = vsin300 [downwards] = -vsin300 [upwards]
change in momemtum= m(vsin30 - (-vsin30))
=m2vsin30 =mv {downwards} [ since sin30 = 1/2]
so, taking only vertical component
initial velocity = vsin300 [upwards]
final velocity = vsin300 [downwards] = -vsin300 [upwards]
change in momemtum= m(vsin30 - (-vsin30))
=m2vsin30 =mv {downwards} [ since sin30 = 1/2]
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