In how many ways can a number 6084 be written as a product of two different factors ? op 1: 27
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First find the prime factors of 6084
2*3042
2*2*1521
2*2*3*507
2*2*3*3*169
2*2*3*3*13*13
2^2*3^2*13^2
Number of factors = (2+1)*(2+1)*(2+1) = 3*3*3 = 27
Using each of these factors, we can write 6084 as a product of 2 factors.
Half of these will remain same.
Let us take a simple example, 6
number of factors = 4
1,2,3,6
can be written as
1*6
2*3
We cant repeat 6*1 and 3*2 as they are already taken.
Hence only 2 ways.
Another example: take 9.
Number of factors = 3
1,3,9
can be written as
1*9 only.
Hence only 1 way.
So it turnsout ot be number of factors/2 if number of factors is even and
(number of factors-1)/2 if number of factors is odd.
Therefore: 27-1/2 = 26/2 = 13 .
2*3042
2*2*1521
2*2*3*507
2*2*3*3*169
2*2*3*3*13*13
2^2*3^2*13^2
Number of factors = (2+1)*(2+1)*(2+1) = 3*3*3 = 27
Using each of these factors, we can write 6084 as a product of 2 factors.
Half of these will remain same.
Let us take a simple example, 6
number of factors = 4
1,2,3,6
can be written as
1*6
2*3
We cant repeat 6*1 and 3*2 as they are already taken.
Hence only 2 ways.
Another example: take 9.
Number of factors = 3
1,3,9
can be written as
1*9 only.
Hence only 1 way.
So it turnsout ot be number of factors/2 if number of factors is even and
(number of factors-1)/2 if number of factors is odd.
Therefore: 27-1/2 = 26/2 = 13 .
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