Question

a body of mass 10 kg moving with the velocity of 4m/s and increases its velocity to 8 m/s in 1 second find the force applied on body

Answer 1

Given :

• Initial velocity (u) = 4 m/s
• Final velocity (v) = 8 m/s
• Time (t) = 1 second
• Mass of a body (m) = 10 kg

To find :

• Acceleration (a) &
• Force applied (F)

According to the question,

→ v = u + at

Where,

• v stands for Final velocity
• u stand for Initial velocity
• a stands for Acceleration
• t stands for Time

→ Substituting the values,

→ 8 = 4 + a × 1

→ 8 - 4 = 1a

→ 4 = 1a

→ 4 ÷ 1 = a

→ 4 = a

.°. The acceleration is 4 m/s²..

Now,

→ Force = Mass × Acceleration

Or,

→ F = ma

→ Substituting the values,

→ F = 10 × 4

→ F = 40 N

So,the force applied on body is 40 Newton.

______________________________

Answer 2

Answer:

ANSWER

Given , Mass of object ,m=10 kg

Velocity of object , v=20ms

−1

Initial Kinetic energy , K

1

=

2

1

×10×20

2

=2000 J

Now Final mass ,m

2

=20 kg

Final Velocity , v

2

=10m/s

Final Kinetic energy , K

2

=

2

1

×20×10

2

=1000 J

Required Ratio=

K

2

K

1

=

1000

2000

=2