A body of mass 100 g is projected vertically upwards with an initial velocity of 49m/s find i) force of gravity on the body ii) magnitude and direction of acceleration of the body iii) vertical height attained by the body iv) total time of flight
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Mass = 100g = 0.1kg
Force by gravity will be negative as motion of the body is in direction opposite to the motion of the body.
F = ma = -0.1×10 =-1N
The magnitude and direction of acceleration of the body at all points during it's vertical motion will be g downwards that is 10m/s^2 downwards.
H = u^2/2g = (49)^2/20 = 120.05m
Total time of flight = 2u/g = 2×49/10 = 9.8 seconds.
Hope this helps.
✌
Force by gravity will be negative as motion of the body is in direction opposite to the motion of the body.
F = ma = -0.1×10 =-1N
The magnitude and direction of acceleration of the body at all points during it's vertical motion will be g downwards that is 10m/s^2 downwards.
H = u^2/2g = (49)^2/20 = 120.05m
Total time of flight = 2u/g = 2×49/10 = 9.8 seconds.
Hope this helps.
✌
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